((a^-7a^5)+(b^3a^-3))/a^-2b^4

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Solution for ((a^-7a^5)+(b^3a^-3))/a^-2b^4 equation: 


D( x )

a^-2 = 0

a^-2 = 0

a^-2 = 0

a^-2 = 0

x naleu017Cy do R

x belongs to the empty set

b^4*((a^-7*a^5+a^-3*b^3)/(a^-2)) = 0

x belongs to the empty set

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